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TS EAMCET 2023 Question Paper May 12 Shift 1 PDF is available here for download. TS EAMCET 2023 Question Paper consisted of 160 questions carrying 1 mark each. TS EAMCET 2023 Question Paper May 12 Shift 1 PDF for MPC includes three subjects, Physics, Chemistry and Mathematics. The Physics and Chemistry section of the paper includes 40 questions each while the Mathematics section includes a total of 80 questions.
TS EAMCET 2023 Question Paper May 12 Shift 1 PDF
TS EAMCET 2023 Question Paper PDF | TS EAMCET 2023 Answer Key PDF |
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TS EAMCET Questions
1. If the line x cos α + y sin α = 2√3 is tangent to the ellipse \(\frac{x^2}{16} + \frac{y^2}{8} = 1\) and α is an acute angle then α =
If the line x cos α + y sin α = 2√3 is tangent to the ellipse \(\frac{x^2}{16} + \frac{y^2}{8} = 1\) and α is an acute angle then α =
\(\frac{π}{6}\)
\(\frac{π}{4}\)
\(\frac{π}{3}\)
\(\frac{π}{2}\)
2. The orthocenter of the triangle whose sides are given by x + y + 10 = 0, x - y - 2 = 0 and 2x + y - 7 = 0 is
The orthocenter of the triangle whose sides are given by x + y + 10 = 0, x - y - 2 = 0 and 2x + y - 7 = 0 is
(-4, -3)
(-4, -6)
(4,6)
(3,6)
3. 5 persons entered a lift cabin in the cellar of a 7-floor building apart from cellar. If each of the independently and with equal probability can leave the cabin at any floor out of the 7 floors beginning with the first, then the probability of all the 5 persons leaving the cabin at different floors is
5 persons entered a lift cabin in the cellar of a 7-floor building apart from cellar. If each of the independently and with equal probability can leave the cabin at any floor out of the 7 floors beginning with the first, then the probability of all the 5 persons leaving the cabin at different floors is
\(\frac{360}{2401}\)
\(\frac{5}{54}\)
\(\frac{51}{71}\)
\(\frac{5}{18}\)
4. The energy of second orbit of hydrogen atom is -5.45x10-19 J. What is the energy of first orbit of Li2+ ion (in J)
-1.962x10-18
-1.962x10-17
-3.924x10-17
-3.924x10-18
5. The roots of the equation x4 + x3 - 4x2 + x + 1 = 0 are diminished by h so that the transformed equation does not contain x2 term. If the values of such h are α and β, then 12(α - β)2 =
The roots of the equation x4 + x3 - 4x2 + x + 1 = 0 are diminished by h so that the transformed equation does not contain x2 term. If the values of such h are α and β, then 12(α - β)2 =
35
25
105
115
6. If i=√-1 then
\[Arg\left[ \frac{(1+i)^{2025}}{1+i^{2022}} \right] =\]
If i=√-1 then
\[Arg\left[ \frac{(1+i)^{2025}}{1+i^{2022}} \right] =\]\(\frac{-π}{4}\)
\(\frac{π}{4}\)
\(\frac{3π}{4}\)
\(\frac{-3π}{4}\)
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