Resultant Vector Formula: Vector Quantity & Solved Examples

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Resultant Vector Formula is used to obtain the resultant value of two or more vectors based on their directions with respect to each other. When two or more forces operate on a body, the resultant force or net force is the sum of all the forces that generate the effect. To get the resultant value of two or more vectors, we apply the resultant vector formula. The resulting vector formula can be used in physics, engineering and mathematics. The three resultant vector formulas are:

R = A + B

R = A - B

R2 = A2 + B2 + 2ABCos Θ

The interaction of several force vectors on a body is an example of the resultant vector, and the resulting vector is obtained using this formula.

Key Takeaways: Resultant Vector formula, Net force, Resultant force, Magnitude, Unit vector, Direction, Momentum, Velocity.

What is Vector Quantity?

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Vector Quantity is a physical quantity that is specified not only by its magnitude but also by its direction. A vector quantity whose magnitude is equal to one and has direction is called a unit vector.

Examples of vector quantity are-

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What is the Resultant Vector Formula?

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The resultant vector formula may be divided into three types on the basis of the orientation of the vectors. These formulae are applicable to vectors pointing in the same direction, vectors pointing in opposing directions, and vectors that are inclined to each other.

Resultant Vector Formula 1

If the vectors are aligned in the same direction then the resulting vector can be obtained by simply adding them. 

Let, A and B are the same-direction vectors, while R is the resulting vector. So, 

R = A + B

Resultant Vector Formula 2

The vectors that are aligned in opposite directions are subtracted from each other to produce the resulting vector. Let, vector B is in the opposite direction of vector A. So, the resultant vector R is

R = A - B

Resultant Vector Formula 3

If the given vectors are inclined to each other then the resultant vector can be obtained by using the formula below. Here, R is the resultant vector, and A and B are inclined at an angle Θ to each other.

R2 = A2 + B2 + 2ABCos Θ

Resultant Vector Formula 3

Resultant Vector Formula 3

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Things to Remember

  • A vector quantity is a physical quantity that has both direction and magnitude.
  • When two or more forces act on a body, the resulting force, also known as the net force, is equal to the total of all the forces that produce the effect.
  • The resultant vector of the vectors that are aligned in the same direction can be evaluated by simply adding the two vectors. R = A + B
  • Vectors that are aligned in opposite directions are subtracted from each other to get the final resultant vector. R = A - B
  • Compute vectors inclined to each other using the formula below to get the resultant vector. In this case, R is the resulting vector, and A and B are at an angle to each other. R2 = A2 + B2 + 2ABCosΘ

Previous Year Questions

  1. If the range and time period of projectile are related to R=5T2, then the angle…? [RPET 2002]
  2. The acceleration a of moving body from rest is 2 (t - 1). Then, the velocity at 5 s will be…?  [RPET 2002]
  3. A particle is projected with velocity 100m is at 30. Time of flight is…? [UGET 2006]
  4. Two boys are standing at ends A and B of a ground where AB=200m. The boy at B starts…? [UGET 2014]
  5. The range of a particle projected at an angle of 15 degree with the horizontal is 1.5 km. Its range…? [UGET 2008]
  6. A particle is moving eastward with velocity 5ms−1 In 10 s the velocity changes to…? [UGET 2012]
  7. Two vectors have magnitudes 3 and 5. If angle between them is 60, then the dot product…? [JCECE 2004]
  8. Two stones are projected with the same speed but making different angles with the horizontal…? [BCECE 2008]
  9. At what angle must the two forces (x + y) and (x - y) act so that the resultant may be…? [JCECE 2010]
  10. A bullet of mass 0.1kg is fired with a speed of 100m/s. The mass of gun being…? [BCECE 2004]
  11. Two equal vectors have a resultant equal to either of them, then the angle between…? [BCECE 2007]
  12. A body is projected at such angle that the horizontal range is three times the greatest…? [BCECE 2007]
  13. A can is moving horizontally along a straight line with constant speed 30m/s. A projectile…? [BCECE 2006]
  14. The (x,y,z) coordinates of two points A and B are given respectively as…?  [BCECE 2007]
  15. A ball thrown by one player reaches the other in 2s. The maximum height attained…? [UPSEE 2008]
  16. A particle is moving in a circle of radius R with constant speed v. If radius is doubled…? [BCECE 2005]
  17. A wet open umbrella is held vertical and it whirled about the handle at a uniform rate of…? [BHU UET 2001]
  18. A particle is thrown vertically upwards. Its velocity at half of the height is…? [BHU UET 2007]
  19. A particle is moving along a circular path of radius 5m with a uniform speed…? [BHU UET 2008]
  20. A 100m long train is moving with a uniform velocity of 45km/h. The time taken…? [BHU UET 2004]

Sample Questions 

Ques: On a straight road, an automobile starts from point A and travels west for 20 seconds, arriving at position B, which is 200 metres distant. After 30 seconds, the automobile returns to the east, arriving at location C, which is 800 metres away from B. What is the car's displacement from point A? (2 Marks)

Ans: The automobile leaves point A and travels west for 20 seconds, arriving at location B, which is 200 metres distant. This corresponds to a -200 m displacement.

After 30 seconds, the automobile returns to the east, arriving at location C, which is 800 metres away from B. This corresponds to a displacement of +800 metres.

As a result, the car's overall displacement is -200 +800 = + 600 m.

Ques: Find the resultant of the vectors 4i + 3j -5k and 8i + 6j - 10k. (2 Marks)

Ans: Given two vectors are:

A = 4i + 3j - 5k and B = 8i + 6j - 10k

Because the direction ratios of the two vectors are equal, the two vectors are pointing in the same direction.

R = A + B

= (4i+3j-5k) + (8i+6j-10k)

= 12i+9j -15k

Ques: Two vectors, F1 = 20 N and F2 = 30 N, have directions as shown in the figure below. Determine the resultant of components of vectors in the x-axis and y-axis. (3 Marks)
Two vectors, F1 = 20 N and F2 = 30 N, have directions

Ans: Given that-

F1 = 20 Newton

Angle between F1 and x axis = 30°

F2 = 30 Newton

Angle between F2 and x axis =30°

F1x = F1 cos 30°= (20)(0.5√3) = 10√3 Newton (plus sign because it points to the x-axis)

F1y = F1 sin 30° = (20)(0.5) = 10 Newton ( plus sign because it points to the +y axis)

F2x = F2 cos 30° = (30)(0.5√3) = -15√3 Newton (plus sign because it points to the -x axis)

F2y = F2 sin 30° = (30)(0.5) = 15 Newton (plus sign because it points to the +y axis)

The resultant of the x component is:

Fx = F1x+F2x

= 10√3 N – 15√3 N 

= -5√3 N

The resultant of the y component is:

Fy = F1y + F2y

= 10N + 15N 

= 25 N

Ques: Determine the resultant of two vectors with magnitudes of 5 and 6 units and an angle of 60 degrees between them. (3 Marks)

Ans: The two vectors are 

A = 5 units, 

B = 6 units 

the angle Θ = 60°.

R2 = A2 + B2 + 2ABCos Θ

= 52 + 62 + 2 × 5 × 6 × Cos60°

= 25 + 36 + 60*1/2

= 61 + 30

R2 = 91

\(R = \sqrt{91} \)

Ques: Someone riding a motorbike 6 kilometres north and then 8 kilometres east from their residence. Determine the person's ultimate position based on their beginning position. (3 Marks)
person's ultimate position based on their beginning position

Ans: Given that: 

A = 6 

B = 8

The angle Θ = 90°.

R2 = 62 + 82 + 2 x 6 x 8 x Cos 90°

\(R = \sqrt{36 + 64}\)

\(R = \sqrt{100}\)

R = 10 km , northeast

Ques: A car travels from A to B along 30 km north, then 60 km east, then 110 km south. Calculate the displacement of the car from A to D. (3 Marks)

Ans: AA’ = 60 km

A’D = 110 km – 30 km 

= 80 km

R2 = (AA’)2 + (A’D)2

R2 = (60)2 + (80)2

\(R = \sqrt {3600 + 6400}\)

\(R = \sqrt{10000}\)

R = 100

displacement of the car from A to D

Ques: Sabrina took a 75-meter trek east. She then walked 25 metres while turning 30 degrees to the left. Determine Sabrina's displacement vector's magnitude. (3 Marks)

Ans: Given that- 

A = 75 meter

B = 25 meter

The angle Θ = 30°.

R2 = A2 + B2 + 2ABCos 30°

R2 = 752 + 252 + 2 (75)(25) \(\frac{\sqrt{3}}{2}\)

\(R = \sqrt{5625 +625 +3247.5}\)

R = 97.46 meter

Ques: Find the angle alpha and the magnitude of a resultant vector. (5 Marks)
angle alpha and the magnitude of a resultant vector

Ans: 

angle alpha

magnitude of a resultant vector

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CBSE CLASS XII Related Questions

  • 1.
    A conductor of length \( l \) is connected across an ideal cell of emf E. Keeping the cell connected, the length of the conductor is increased to \( 2l \) by gradually stretching it. If R and \( R' \) are initial and final values of resistance and \( v_d \) and \( v_d' \) are initial and final values of drift velocity, find the relation between:
    \( R' \) and \( R \)
    \( R' = 4R \)


      • 2.
        A 1 cm straight segment of a conductor carrying 1 A current in \( x \)-direction lies symmetrically at the origin of Cartesian coordinate system. The magnetic field due to this segment at point (1m, 1m, 0) is:

          • \( 1.0 \times 10^{-9} \, \text{T} \)
          • \( -1.0 \times 10^{-9} \, \text{T} \)
          • \( \frac{5.0}{\sqrt{2}} \times 10^{-10} \, \text{T} \)
          • \( -\frac{5.0}{\sqrt{2}} \times 10^{-10} \, \text{T} \)

        • 3.
          Two wires P and Q are made of the same material. Wire Q has twice the diameter and half the length of wire P. If the resistance of wire P is \( R \), the resistance of wire Q will be:

            • \( R \)
            • \( \frac{R}{2} \)
            • \( \frac{R}{8} \)
            • \( 2R \)

          • 4.
            Consider three metal spherical shells A, B, and C, each of radius \( R \). Each shell has a concentric metal ball of radius \( R/10 \). The spherical shells A, B, and C are given charges \( +6q, -4q, \) and \( 14q \) respectively. Their inner metal balls are also given charges \( -2q, +8q, \) and \( -10q \) respectively. Compare the magnitude of the electric fields due to shells A, B, and C at a distance \( 3R \) from their centers.


              • 5.
                A proton moving with velocity \( V \) in a non-uniform magnetic field traces a path as shown in the figure. The path followed by the proton is always in the plane of the paper. What is the direction of the magnetic field in the region near points P, Q, and R? What can you say about relative magnitude of magnetic fields at these points?
                proton moving with velocity V in a non-uniform magnetic field


                  • 6.
                    Answer the following giving reason:
                    (a) All the photoelectrons do not eject with the same kinetic energy when monochromatic light is incident on a metal surface.
                    (b) The saturation current in case (a) is different for different intensity.
                    (c) If one goes on increasing the wavelength of light incident on a metal sur face, keeping its intensity constant, emission of photoelectrons stops at a certain wavelength for this metal.

                      CBSE CLASS XII Previous Year Papers

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