Question:
What are X and Y respectively in the following set of reactions? (R--Br + \(CH_{3}CH_{2}O^-\) \(\rightarrow\) X; R--Br + \((CH_{3})_{3}CO^-\) \(\rightarrow\) Y)
What are X and Y respectively in the following set of reactions? (R--Br + \(CH_{3}CH_{2}O^-\) \(\rightarrow\) X; R--Br + \((CH_{3})_{3}CO^-\) \(\rightarrow\) Y)
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Bulky bases usually favor elimination (\(E2\)), while small nucleophiles favor substitution (\(S_N2\)).
Updated On: Jun 7, 2026
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The Correct Option is B
Solution and Explanation
Concept:
Small strong nucleophiles favor substitution reactions, whereas bulky bases favor elimination reactions.
Step 1: Reaction with ethoxide ion.
\[ CH_3CH_2O^- \] is a strong nucleophile and relatively less bulky. Hence, it favors: \[ S_N2 \] reaction producing an ether.
Step 2: Reaction with tert-butoxide ion.
\[ (CH_3)_3CO^- \] is bulky and acts mainly as a base. Hence, it favors: \[ E2 \] elimination to produce an alkene. Thus, option 2 correctly represents the products.
Step 1: Reaction with ethoxide ion.
\[ CH_3CH_2O^- \] is a strong nucleophile and relatively less bulky. Hence, it favors: \[ S_N2 \] reaction producing an ether.
Step 2: Reaction with tert-butoxide ion.
\[ (CH_3)_3CO^- \] is bulky and acts mainly as a base. Hence, it favors: \[ E2 \] elimination to produce an alkene. Thus, option 2 correctly represents the products.
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