(a) Capacitances of the given capacitors: C1 = 2 pF, C2 = 3 pF and C3 = 4 pF For the parallel combination of the capacitors, equivalent capacitor is given by Ceq the algebraic sum, Therefore Ceq=C1+ C2+C3=2+3+4=9 pF
Therefore, total capacitance of the combination is 9 pF.
(b) Supply voltage, V = 100 V
The voltage through all the three capacitors is same = V = 100 V Charge on a capacitor of capacitance C and potential difference V is given by the relation, q = VC
For C = 2 pF, charge = VC = 100 × 2 = 200 pC = 2 × 10–10 C
For C = 3 pF, charge = VC = 100 × 3 = 300 pC = 3 × 10–10 C
For C = 4 pF, charge = VC = 100 × 4 = 400 pC = 4 × 10–10 C
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Top Questions on electrostatic potential and capacitance
Capacitors commonly known as Condensers are passive components, similar to a resistor. In capacitors, charges are usually stored in the form of an "electrical field". Electrical and electronic circuits depend on the same which is made up of two parallel metal plates that are not connected to one another. The two plates are separated by a non-conducting insulating medium called dielectric.
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