Select Goal &
City
Select Goal
Explore
Question:
The speed of sound in an ideal gas at a given temperature T is v. The rms speed of gas molecules at that temperature is vrms. The ratio of the velocities v and vrms for helium and oxygen gases are X and X' respectively. Then \(\frac{X}{X'}\) is equal to
The speed of sound in an ideal gas at a given temperature T is v. The rms speed of gas molecules at that temperature is vrms. The ratio of the velocities v and vrms for helium and oxygen gases are X and X' respectively. Then \(\frac{X}{X'}\) is equal to
Updated On: Oct 6, 2024
- \(\frac{5}{\sqrt{21}}\)
- \(\sqrt{\frac{5}{21}}\)
- \(\frac{21}{5}\)
- \(\frac{21}{\sqrt{5}}\)
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
The correct answer is (A) : \(\frac{5}{\sqrt{21}}\).
Was this answer helpful?
0
6
Top Questions on Thermodynamics
- Which of the following is correct for adiabatic free expansion against vacuum?
- JEE Main - 2024
- Chemistry
- Thermodynamics
- In an air-standard Otto cycle, the pressure and temperature of air just before the compression stroke are 200 kPa and 26.85 °C, respectively. The combustion process is assumed to be a constant volume process, where 1.02 MJ/kg heat is added. The cycle efficiency is 50%. The adiabatic index \(γ\) and specific heat at constant volume \(C_v\) can be considered to be constant during the process (corresponding values taken at the mean cycle temperature).
Assuming that the ideal gas law is applicable, \(γ = \frac 43\) and \(c_v= 0.85\ kJ/kg-K\), the maximum pressure (in MPa) reached during the cycle is _____ . (Rounded off to 1 decimal place)- GATE PI - 2024
- General Engineering
- Thermodynamics
- Match List I with List II
List-I
(Process)List-II
(Conditions)(A) Isothermal process (I) No heat exchange (B) Isochoric process (II) Carried out at constant temperature (C) Isobaric process (III) Carried out at constant volume (D) Adiabatic process (IV) Carried out at constant pressure
Choose the correct answer from the options given below:- NEET (UG) - 2024
- Chemistry
- Thermodynamics
- Consider the two statements (Assume density of water to be constant):
Statement 1: A capillary tube is first dipped in hot water and then dipped in cold water. The rise is higher in hot water.
Statement 2: Capillary tube is first dipped in cold water and then in hot water. The rise is higher in cold water.- JEE Main - 2024
- Physics
- Thermodynamics
- The Pressure (P) versus volume (V) of thermodynamic process shown in figure. The select the correct options (Take γ= 1.1)
- JEE Main - 2024
- Physics
- Thermodynamics
View More Questions
Questions Asked in KCET exam
- A cubical Gaussian surface has side of length a = 10 cm. Electric field lines are parallel to x-axis as shown. The magnitudes of electric fields through surfaces ABCD and EFGH are 6kNC-1 and 9kNC-1 respectively. Then the total charge enclosed by the cube is
[Take ε0 = 9 × 10-12 Fm-1]
- KCET - 2023
- Gauss Law
- A sample of water is found to contain 5.85% \((\frac{w}{w})\) of AB (molecular mass 58.5) and 9.50% \((\frac{w}{w})\) XY2 (molecular mass 95). Assuming 80% ionisation of AB and 60% ionisation of XY2 , the freezing point of water sample is
[Given : Kf for water 1.86 K kg mol-1 , Freezing point of pure water is 273 K and A, B and Y are monovalent ions]- KCET - 2023
- Colligative Properties
- \(aMnO^{-}_4+bS_2O_{3}^-+H_2O\rightarrow xMnO_2+ySO_{4}^-+zOH^-\)
a and y respectively are- KCET - 2023
- Redox reactions
- \(\int\sqrt{\cosec x-\sin x}\ dx=\)
- KCET - 2023
- Definite Integral
- A metallic rod of length 1 m held along east-west direction is allowed to fall down freely. Given horizontal component of earth’s magnetic field BH = 3 × 10-5 T. The emf induced in the rod at an instant t = 2s after it is released is ( Take g = 10 ms-2 )
- KCET - 2023
- Faradays laws of induction
View More Questions
SUBSCRIBE TO OUR NEWS LETTER
COLLEGE NOTIFICATIONSEXAM NOTIFICATIONSNEWS UPDATES
Download the Collegedunia app on 
© 2024 Collegedunia Web Pvt. Ltd. All Rights Reserved