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The reaction $Pb \left( NO _3\right)_2$ and $NaCl$ in water produces a precipitate that dissolves upon the addition of $HCl$ of appropriate concentration The dissolution of the precipitate is due to the formation of
The reaction $Pb \left( NO _3\right)_2$ and $NaCl$ in water produces a precipitate that dissolves upon the addition of $HCl$ of appropriate concentration The dissolution of the precipitate is due to the formation of
Updated On: Jun 4, 2024
- $PbCl _2$
- $PbCl _4$
- $\left[ PbCl _4\right]^{2-}$
- $\left[ PbCl _6\right]^{2-}$
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The Correct Option is C
Solution and Explanation
When lead ions (Pb2+) react with chloride ions (Cl−), a white precipitate of lead(II) chloride (PbCl2) forms.
This precipitate is soluble in concentrated hydrochloric acid due to formation of tetrachloroplumbate (II) ion
So the correct answer option is (C)
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