Question:
The reaction of 1-bromohexane with aqueous \(NaOH\) solution follows the order
The reaction of 1-bromohexane with aqueous \(NaOH\) solution follows the order
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Primary alkyl halides usually undergo \(S_N2\) reactions, which follow second order kinetics because both substrate and nucleophile affect the rate.
Updated On: Jun 25, 2026
- zero order kinetics
- first order kinetics
- second order kinetics
- third order kinetics
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The Correct Option is C
Solution and Explanation
Step 1: Identify the type of alkyl halide.
1-bromohexane is a primary alkyl halide: \[ CH_3(CH_2)_5Br \] Primary alkyl halides generally undergo nucleophilic substitution through: \[ S_N2 \] mechanism.
Step 2: Understand the \(S_N2\) mechanism.
In the \(S_N2\) reaction, both: alkyl halide and \[ OH^- \] participate in the rate determining step.
Hence, the rate law is: \[ \text{Rate}=k[1\text{-bromohexane}][OH^-] \]
Step 3: Determine overall order.
The reaction is first order with respect to: \[ 1\text{-bromohexane} \] and first order with respect to: \[ OH^- \] Therefore, total order is: \[ 1+1=2 \]
Step 4: Final conclusion.
Hence, the reaction follows \[ \boxed{\text{second order kinetics}} \]
1-bromohexane is a primary alkyl halide: \[ CH_3(CH_2)_5Br \] Primary alkyl halides generally undergo nucleophilic substitution through: \[ S_N2 \] mechanism.
Step 2: Understand the \(S_N2\) mechanism.
In the \(S_N2\) reaction, both: alkyl halide and \[ OH^- \] participate in the rate determining step.
Hence, the rate law is: \[ \text{Rate}=k[1\text{-bromohexane}][OH^-] \]
Step 3: Determine overall order.
The reaction is first order with respect to: \[ 1\text{-bromohexane} \] and first order with respect to: \[ OH^- \] Therefore, total order is: \[ 1+1=2 \]
Step 4: Final conclusion.
Hence, the reaction follows \[ \boxed{\text{second order kinetics}} \]
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