Question:
The product Z of the given reaction sequence is:
\(C_2H_4 \xrightarrow[(ii)\ KMnO_4/H^+]{(i)\ H_2O/H^+} X \xrightarrow{SOCl_2} Y \xrightarrow{(C_2H_5)_2Cd} Z\)
The product Z of the given reaction sequence is:
\(C_2H_4 \xrightarrow[(ii)\ KMnO_4/H^+]{(i)\ H_2O/H^+} X \xrightarrow{SOCl_2} Y \xrightarrow{(C_2H_5)_2Cd} Z\)
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Dialkyl cadmium reagents stop at ketone stage, unlike Grignard reagents which further react to alcohols.
Updated On: Jun 9, 2026
- An acid chloride
- A ketone
- An aldehyde
- An ester
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The Correct Option is B
Solution and Explanation
Concept:
Ethene undergoes hydration followed by oxidation to a carboxylic acid, which is converted to an acid chloride and then reacts with a dialkyl cadmium reagent to give a ketone.
Step 1: Identify intermediate X.
\(C_2H_4 \xrightarrow{H_2O/H^+} C_2H_5OH \xrightarrow{KMnO_4/H^+} CH_3COOH\) So, \(X = CH_3COOH\)
Step 2: Convert X to Y.
\(CH_3COOH \xrightarrow{SOCl_2} CH_3COCl\) So, \(Y = CH_3COCl\)
Step 3: Reaction with dialkyl cadmium.
\(CH_3COCl + (C_2H_5)_2Cd \rightarrow CH_3COC_2H_5\) So, \(Z = CH_3COC_2H_5\) (a ketone) \[ \boxed{\text{A ketone}} \]
Step 1: Identify intermediate X.
\(C_2H_4 \xrightarrow{H_2O/H^+} C_2H_5OH \xrightarrow{KMnO_4/H^+} CH_3COOH\) So, \(X = CH_3COOH\)
Step 2: Convert X to Y.
\(CH_3COOH \xrightarrow{SOCl_2} CH_3COCl\) So, \(Y = CH_3COCl\)
Step 3: Reaction with dialkyl cadmium.
\(CH_3COCl + (C_2H_5)_2Cd \rightarrow CH_3COC_2H_5\) So, \(Z = CH_3COC_2H_5\) (a ketone) \[ \boxed{\text{A ketone}} \]
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