Concept:
To name an alkane, identify the longest carbon chain (parent chain), number it to give substituents the lowest possible locants, and list them alphabetically.
Step 1: Identify the longest chain.
For the provided structure:
The longest chain consists of 8 carbon atoms, making it an octane.
Step 2: Number the chain and identify substituents.
By numbering the octane chain from the left side, the methyl groups are located at carbons 2, 5, and 6. Numbering from the right would result in higher locants (3, 4, 7).
Substituents: 2, 5, 6-Trimethyl
Step 3: Assemble the IUPAC name.
Combining the substituents and parent chain gives 2, 5, 6-Trimethyloctane.
\[
\boxed{2, 5, 6-\text{Trimethyloctane}}
\]