Question:
The correct IUPAC names of the compounds X and Y given below are respectively
The correct IUPAC names of the compounds X and Y given below are respectively
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In IUPAC nomenclature:
\[
-OH
\]
has higher priority than alkyl or phenyl substituents.
Therefore numbering must always give the hydroxyl group the lowest possible locant.
Updated On: Jun 17, 2026
- 3-Methyl-4-ethylheptane ; 1-Phenylbutan-2-ol
- 4-Ethyl-3-Methylheptane ; 1-Phenylbutan-2-ol
- 3-(sec-butyl)-hexane ; 2-Hydroxy-1-phenylbutane
- 3-Methyl-4-Ethylheptane ; 2-Hydroxybutylbenzene
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The Correct Option is B
Solution and Explanation
Concept:
IUPAC nomenclature requires:
• Identification of the longest carbon chain
• Assignment of lowest possible locants
• Alphabetical ordering of substituents
• Priority-based naming of functional groups
Step 1: Naming compound X. The longest continuous chain contains: \[ 7 \text{ carbon atoms} \] Therefore the parent hydrocarbon is: Heptane Substituents present are: Ethyl and Methyl Numbering from the appropriate end gives: \[ 4\text{-Ethyl} \] and \[ 3\text{-Methyl} \] According to alphabetical order: \[ \boxed{4\text{-Ethyl-3-Methylheptane}} \]
Step 2: Naming compound Y. The principal functional group is: \[ -OH \] Hence alcohol receives suffix priority. The longest chain containing the hydroxyl group consists of four carbons. Parent chain: Butan-2-ol Phenyl substituent occurs at carbon-1. Therefore: \[ \boxed{1\text{-Phenylbutan-2-ol}} \]
Step 3: Check the options. Only option (B) contains both correct names.
Step 4: Final conclusion. \[ \boxed{\text{Option (B)}} \]
• Identification of the longest carbon chain
• Assignment of lowest possible locants
• Alphabetical ordering of substituents
• Priority-based naming of functional groups
Step 1: Naming compound X. The longest continuous chain contains: \[ 7 \text{ carbon atoms} \] Therefore the parent hydrocarbon is: Heptane Substituents present are: Ethyl and Methyl Numbering from the appropriate end gives: \[ 4\text{-Ethyl} \] and \[ 3\text{-Methyl} \] According to alphabetical order: \[ \boxed{4\text{-Ethyl-3-Methylheptane}} \]
Step 2: Naming compound Y. The principal functional group is: \[ -OH \] Hence alcohol receives suffix priority. The longest chain containing the hydroxyl group consists of four carbons. Parent chain: Butan-2-ol Phenyl substituent occurs at carbon-1. Therefore: \[ \boxed{1\text{-Phenylbutan-2-ol}} \]
Step 3: Check the options. Only option (B) contains both correct names.
Step 4: Final conclusion. \[ \boxed{\text{Option (B)}} \]
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