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Match List I with List IIList-I List-II A. Melting point [K] I. Tl > In > Ga > Al > B B. Ionic Radius [M3/pm] II. B > Tl > Al ≈ Ga ≈ In C. ΔiH1 [kJ mol-1] III. Tl > In > Al > Ga > B D. Atomic Radius [pm] IV. B > Al > Tl > In > Ga
Choose the correct answer from the options given below:
Match List I with List II
Choose the correct answer from the options given below:
| List-I | List-II |
|---|---|
| A. Melting point [K] | I. Tl > In > Ga > Al > B |
| B. Ionic Radius [M3/pm] | II. B > Tl > Al ≈ Ga ≈ In |
| C. ΔiH1 [kJ mol-1] | III. Tl > In > Al > Ga > B |
| D. Atomic Radius [pm] | IV. B > Al > Tl > In > Ga |
Choose the correct answer from the options given below:
Updated On: Nov 18, 2024
- A-III, B-IV, C-I, D-II
- A-II, B-III, C-IV, D-I
- A-IV, B-I, C-II, D-III
- A-I, B-II, C-III, D-IV
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The Correct Option is C
Solution and Explanation
To match the items from List I with List II:
A. Melting point [K]: Based on the trend, Tl > In > Ga > Al > B. (Matches I).
B. Ionic Radius [M$^{+3}$/pm]: Boron has the smallest ionic size, followed by Tl > Al $\approx$ Ga > In (Matches II).
C. $\Delta_i H_1$ [kJ mol$^{-1}$]: Ionization enthalpy follows the trend Tl > In > Al > Ga > B.(Matches III).
D. Atomic Radius [pm]: Atomic radius increases as B > Al > Tl > In > Ga.(Matches IV).
Correct Answer: (3)
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