Question:

In the first order thermal decomposition of $C _{2} H _{5} I (g) \longrightarrow C _{2} H _{4}(g)+ HI (g)$, the reactant in the beginning exerts a pressure of $2$ bar in a closed vessel at $600 \,K$. If the partial pressure of the reactant is $0.1$ bar after $1000$ minutes at the same temperature the rate constant in $\min ^{-1}$ is $(\log 2=0.3010)$

Updated On: Apr 4, 2024
  • $6.0 \times 10^{-4}$
  • $6.0 \times 10^{- 3}$
  • $3 .0 \times 10^{- 3}$
  • $3.0 \times 10^{-4}$
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The Correct Option is C

Solution and Explanation




Since, the reaction is first order,

$k= \frac{2.303}{t} \log \frac{p}{p_{0}-x} $

$k =\frac{2.303}{1000} \log \frac{2}{2-1.9} $

$=\frac{2303}{1000} \log 20$

$k =3 \times 10^{-3} \min ^{-1}$
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Concepts Used:

Rate of a Chemical Reaction

The rate of a chemical reaction is defined as the change in concentration of any one of the reactants or products per unit time.

Consider the reaction A → B,

Rate of the reaction is given by,

Rate = −d[A]/ dt=+d[B]/ dt

Where, [A] → concentration of reactant A

[B] → concentration of product B

(-) A negative sign indicates a decrease in the concentration of A with time.

(+) A positive sign indicates an increase in the concentration of B with time.

Factors Determining the Rate of a Reaction:

There are certain factors that determine the rate of a reaction:

  1. Temperature
  2. Catalyst
  3. Reactant Concentration
  4. Chemical nature of Reactant
  5. Reactant Subdivision rate