Question:
If the Poisson's ratio of the material of a wire is 0.35, then the ratio of the longitudinal and volume strains of the wire is:
If the Poisson's ratio of the material of a wire is 0.35, then the ratio of the longitudinal and volume strains of the wire is:
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Remember:
\[
\text{Volume strain}
=
(1-2\mu)\times \text{Longitudinal strain}.
\]
Updated On: Jun 18, 2026
- \(1:2\)
- \(10:3\)
- \(7:10\)
- \(3:7\)
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The Correct Option is B
Solution and Explanation
Concept:
Volume strain is related to longitudinal strain by
\[
\text{Volume strain}
=
(1-2\mu)
\times
\text{Longitudinal strain}.
\]
where \(\mu\) is Poisson's ratio.
Step 1: Substitute the value of Poisson's ratio.
\[ \mu=0.35. \] \[ 1-2\mu = 1-0.70 = 0.30. \]
Step 2: Find ratio.
Let longitudinal strain be \(L\). Then \[ V=0.3L. \] Therefore \[ L:V = 1:0.3. \] Multiplying by 10, \[ L:V = 10:3. \] Hence \[ \boxed{10:3}. \]
Step 1: Substitute the value of Poisson's ratio.
\[ \mu=0.35. \] \[ 1-2\mu = 1-0.70 = 0.30. \]
Step 2: Find ratio.
Let longitudinal strain be \(L\). Then \[ V=0.3L. \] Therefore \[ L:V = 1:0.3. \] Multiplying by 10, \[ L:V = 10:3. \] Hence \[ \boxed{10:3}. \]
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