The heat required to convert 8 g of ice at a temperature of \( -20^\circ\text{C} \) to steam at \( 100^\circ\text{C} \) is
[Specific heat capacity of ice = \( 2100 \, \text{Jkg}^{-1}\text{K}^{-1} \), specific heat capacity of water = \( 4200 \, \text{Jkg}^{-1}\text{K}^{-1} \), latent heat of fusion of ice = \( 336 \times 10^3 \, \text{Jkg}^{-1} \) and latent heat of steam = \( 2.268 \times 10^6 \, \text{Jkg}^{-1} \)]