List of top Physics Questions on Youngs double slit experiment

In Young's double slit experiment, carried out with light of wavelength 5000Å, the distance between the slits is 0.3 mm and the screen is at 200 cm from the slits. The central maximum is at x = 0 cm. The value of x for third maxima is ............. mm.

In Young’s double slit experiment, light from two identical sources is superimposing on a screen. The path difference between the two lights reaching a point on the screen is \( \frac{7\lambda}{4} \). The ratio of the intensity of the fringe at this point with respect to the maximum intensity of the fringe is:

The maximum elongation of a steel wire of 1 m length if the elastic limit of steel and its Young’s modulus, respectively, are 8 × 10⁸ N m^–2 and 2 × 10¹¹ N m^–2, is :

A metallic bar of Young’s modulus, 0.5 × 10¹¹ N m^–2 and coefficient of linear thermal expansion 10^–5 °C^–1, length 1 m and area of cross-section 10^–3 m² is heated from 0°C to 100°C without expansion or bending. The compressive force developed in it is :

If the monochromatic source in Young's double slit experiment is replaced by white light, then coloured fringes. (3) there will be a central bright white fringe surrounded by a few coloured fringes. (4) all bright fringes will be of equal width.

In a Young’s double slit experiment, each of the two slits A and B, as shown in the figure, are oscillating about their fixed center and with a mean separation of 0.8 mm. The distance between the slits at time t is given by 𝑑 = (0.8 + 0.04 sin 𝜔𝑡) mm, where 𝜔 = 0.08 rad s −1 . The distance of the screen from the slits is 1 m and the wavelength of the light used to illuminate the slits is 6000 Å. The interference pattern on the screen changes with time, while the central bright fringe (zeroth fringe) remains fixed at point O.

If the area of cross-section is halved and length of a wire having Young's modulus Y is doubled, then its new Young's modulus will be

With rise in temperature the young's modulus of elasticity

In YDSE, intensity at two sources are in ratio of \(1: 9\). if source are incoherent then intensity at central point is \(I_1\), and if sources are coherent (and phase differs by \(60°\)) then intensity at central point is \(12\) then \(\frac{I_1}{I_2}\) is

The intensity at each slit is equal for a YDSE and it is maximum \(I_{max}\) at \(7π\) central maxima. If I is intensity for phase difference \(\frac{7π}{2}\) between two waves on screen. Then \(\frac{I}{I_{max}}\) is?

In the Young’s double slit experiment, the intensity of light passing through each of the two double slits is 2 × 10^-2 Wm^-2. The screen-slit distance is very large in comparison with slit-slit distance. The fringe width is β. The distance between the central maximum and a point P on the screen is \(\frac{\beta}{3}\). Then the total light intensity at that point is

Find the α, β, γ in the Y = \(C^\alpha h^\beta G^\gamma,\,\,\) 
\(\gamma\) = Young's Modulus
 \(c\) = speed of Light
 \(h\) = Plank's Constant
 \(G\) = gravitational Constant

Wire A and B have their Young’s moduli in the ratio 1:3, area of cross section in the ratio of 1:2 and lengths in ratio of 3:4. If same force is applied on the two wires to elongate then ratio of elongation is equal to

In a Young's double slit experiment, the intensities at two points, for the path respectively If $I_0$ denotes the intensity produced by each one of the individual slits, then $\frac{I_1+I_2}{I_0}=$_______

In Young's double slits experiment, the position of $5^{\text {th }}$ bright fringe from the central maximum is $5 \,cm$ The distance between slits and screen is $1 \,m$ and wavelength of used monochromatic light is $600 \,mm$ The separation between the slits is:

Young’s modulus of elasticity 𝑌 is expressed in terms of three derived quantities, namely, the gravitational constant 𝐺, Planck’s constant ℎ and the speed of light 𝑐, as 𝑌 = 𝑐^𝛼ℎ^𝛽𝐺^𝛾. Which of the following is the correct option?

As shown in the figure, in Young's double slit experiment, a thin plate of thickness $t=10 \mu m$ and refractive index $\mu=12$ is inserted infront of slit $S_1$ The experiment is conducted in air $(\mu-1)$ and uses a monochromatic light of wavelength $\lambda=500 nm$ Due to the insertion of the plate, central maxima is shifted by a distance of $x \beta_0 \beta_0$ is the fringe-width befor the insertion of the plate The value of the $x$ is ___

Young’s modulus of elasticity 𝑌 is expressed in terms of three derived quantities, namely, the gravitational constant 𝐺, Planck’s constant ℎ and the speed of light 𝑐, as 𝑌 = 𝑐 ^𝛼ℎ ^𝛽𝐺 ^𝛾 . Which of the following is the correct option?

Two light waves of wavelengths 800 and $600 nm$ are used in Young's double slit experiment to obtain interference fringes on a screen placed $7 m$ away from plane of slits If the two slits are separated by $0.35 mm$, then shortest distance from the central bright maximum to the point where the bright fringes of the two wavelength coincide will be ___$mm$

In Young's double slit experiment, two slits $S_1$ and $S_2$ are ' $d$ ' distance apart and the separation from slits to screen is $D$ (as shown in figure) Now if two transparent slabs of equal thickness $0.1 \,mm$ but refractive index $1.51$ and $1.55$ are introduced in the path of beam $(\lambda=4000 \mathring {A})$ from $S_1$ and $S_2$ respectively, The central bright fringe spot will shift by ______number of fringes

An aluminium rod with Young's modulus Y=7.0×10¹⁰ N/m² undergoes elastic strain of 0.04%. The energy per unit volume stored in the rod in SI unit is:

The ratio of intensities at two points P and Q on the screen in a Young’s double slit experiment where phase difference between two wave of same amplitude are \(\frac{π}{3}\) and \(\frac{π}{2}\), respectively are 

For the given YDSE setup. Find the number of fringes by which the central maxima gets shifted from point O.
(Given d = 1 mm D = 1 m λ = 5000 Å)

Figure shows Fraunhofer's diffraction due to a single slit. If first minima is obtained in the direction shown, then the path difference between ray 1 and ray 3 is