\(\text{ The de Broglie wavelength is given by } \lambda = \frac{h}{p}, \text{ where } p \text{ is the momentum.} \\ \text{ A 1\% change in wavelength corresponds to a 1\% change in momentum.} \\ \text{ If the change in momentum is } P, \text{ the initial momentum } p_0 \text{ is given by:}\)
\[\frac{P}{p_0} = 0.01 \implies p_0 = 100 P\]