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HBr and HI reduce sulphuric acid, HCl can reduce $KMnO_4$ and HF can reduce
HBr and HI reduce sulphuric acid, HCl can reduce $KMnO_4$ and HF can reduce
Updated On: Jun 14, 2022
- $H_2SO_4$
- $KMnO_4$
- $K_2Cr_2$
- None of these
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The Correct Option is D
Solution and Explanation
Fluorine, being the most electronegative, its size is very
small. Therefore, it does not have a tendency to loose
electrons. Hence, HF does not act as a reducing agent.
small. Therefore, it does not have a tendency to loose
electrons. Hence, HF does not act as a reducing agent.
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