Question:

Given below are two statements ; one is labelled as Assertion $A$ and the other is labelled as Reason $R$

Assertion A: Photodiodes are used in forward bias usually for measuring the light intensity

Reason R: For a p-n junction diode at applied voltage $V$ the current in the forward bias is more than the current in the reverse bias for $\left|V_2\right|>\pm V \geq\left|V_0\right|$ where $V_0$ is the threshold voltage and $V _2$ is the breakdown voltage

In the light of the above statements, choose the correct answer from the options given below

Updated On: Jul 13, 2024
  • A is true but $R$ is false
  • A is false but $R$ is true
  • Both $A$ and $R$ are true but $R$ is NOT the correct explanation $A$
  • Both $A$ and $R$ are true and $R$ is correct explanation $A$
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The Correct Option is B

Solution and Explanation

Theory based
Photodiodes are operated in reverse bias condition.
For junction current in forward bias (for ) is always greater than current in reverse bias for ) .
Hence Assertion if false but Reason is true
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Concepts Used:

P-n Junction

A P-N junction is an interface or a boundary between two semiconductor material types, namely the p-type and the n-type, inside a semiconductor.

Biasing conditions for the p-n Junction Diode:

in p-n junction diode two operating regions are there:

  • P-type
  • N-type

There are three biasing conditions for p-n junction diode are as follows:

  • Zero bias: When there is no external voltage applied to the p-n junction diode.
  • Forward bias: P-type is connected to positive terminal of the voltage potential while n-type is connected to the negative terminal.
  • Reverse bias: P-type is connected to negative terminal of the voltage potential while n-type is connected to the positive terminal.