Given,
Current = 5A
Time = 20 × 60 = 1200 s
∴ Charge = current × time
= 5 × 1200
= 6000 C
According to the reaction,
Ni2+(aq)+2e- \(\rightarrow\) Ni(s)
58.7 g
Nickel deposited by 2 × 96487 C = 58.71 g
Therefore, nickel deposited by 6000 C = \(\frac{58.71 \times 6000}{2 \times 96487}g\)
= 1.825 g
Hence, 1.825 g of nickel will be deposited at the cathode.
What is the Planning Process?
Galvanic cells, also known as voltaic cells, are electrochemical cells in which spontaneous oxidation-reduction reactions produce electrical energy. It converts chemical energy to electrical energy.
It consists of two half cells and in each half cell, a suitable electrode is immersed. The two half cells are connected through a salt bridge. The need for the salt bridge is to keep the oxidation and reduction processes running simultaneously. Without it, the electrons liberated at the anode would get attracted to the cathode thereby stopping the reaction on the whole.