Question:

A mixture of methylamine and dimethylamine is given to you. The reagents used to separate the components of the mixture are

Updated On: Jun 19, 2024
  • $\ce{CHCl_3 }$ and $\ce{ HCl}$
  • $\ce{C6H5SO_2Cl }$ and $\ce{KOH}$
  • $\ce{C6H5SO_2Cl }$ and $\ce{ HCl}$
  • $\ce{CHCl_3 }$ and $\ce{KOH}$
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The Correct Option is B

Solution and Explanation

A mixture of methylamine (1? amine) and dimethylamine (2? amine) can be separated with the help of $ {C_6H_5SO_2Cl}$ and KOH (Hinsberg's method).
Methylamine will form N-methylbenzenesulphonamide which is soluble in KOH. Dimethylamine will form N,N dimcthylbenzene sulphonamide which is insoluble in KOH.
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Concepts Used:

Amines

Amine is a type of compound which is derived from ammonia (NH3). According to Organic chemistry, they are basically classified as the functional groups of the organic nitrogen compounds that contain nitrogen atoms with a lone pair.

Amine - Types

Primary Amines:

It is formed when one hydrogen atom in ammonia is substituted by an alkyl or aromatic group. Amino acids and methyl amine are the best examples that why aromatic amines include aniline.

Secondary Amines:

Amines that have two organic substitutes either alkyl or aryl ones or both and are bound to the nitrogen together with one hydrogen are termed as secondary amines. For Example, Dimethylamine.

Tertiary Amines:

Tertiary Amines are the amines where the nitrogen consists of three organic substitutes. For example, Trimethylamine and EDTA.