If electric field intensity of a uniform plane electromagnetic wave is given as
\(E = -301.6 \sin(kz - \omega t) \hat{a}_x + 452.4 \sin(k\omega - \omega t) \hat{a}_y \, \frac{V}{m}\)
Then, magnetic intensity ‘H’ of this wave in Am–1 will be :
[Given : Speed of light in vacuum c = 3 × 108ms–1, Permeability of vacuum \(\mu_0 = 4\pi \times 10^{-7}\) NA–2]