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List of top Mathematics Questions on circle asked in BITSAT
The locus of the point of intersection of the lines \(x = a(1 - t^2)/(1 + t^2)\) and \(y = 2at/(1 + t^2)\) (t being a parameter) represents:
BITSAT - 2024
BITSAT
Mathematics
circle
If the straight line
$2x + 3y - 1 = 0$, $x + 2y - 1 = 0$
and
$ax + by - 1 = 0$
form a triangle with origin as orthocentre, then
$(a,b)$
is equal to:
BITSAT - 2024
BITSAT
Mathematics
circle
The distance from the origin to the image of
$(1,1)$
with respect to the line
$x + y + 5 = 0$
is:
BITSAT - 2024
BITSAT
Mathematics
circle
A(3,2,0), B(5,3,2), C(-9,6,-3) are three points forming a triangle. AD, the bisector of angle
$BAC$
meets BC in D. Find the coordinates of D:
BITSAT - 2024
BITSAT
Mathematics
circle
The locus of the mid-point of a chord of the circle
$x^2 + y^2 = 4$
which subtends a right angle at the origin is:
BITSAT - 2024
BITSAT
Mathematics
circle
If \( p \) and \( q \) be the longest and the shortest distance respectively of the point
(-7,2)
from any point
(\(\alpha, \beta\))
on the curve whose equation is
\[ x^2 + y^2 - 10x - 14y - 51 = 0 \]
then the geometric mean (G.M.) of \( p \) is:
BITSAT - 2024
BITSAT
Mathematics
circle
From a point
A(0,3)
on the circle
\[ (x + 2)^2 + (y - 3)^2 = 4 \]
a chord AB is drawn and extended to a point Q such that
AQ = 2AB.
Then the locus of Q is:
BITSAT - 2024
BITSAT
Mathematics
circle
The maximum area of a rectangle inscribed in a circle of diameter \( R \) is:
BITSAT - 2024
BITSAT
Mathematics
circle
The locus of the mid-point of a chord of the circle $x^2+ y^2 = 4$, which subtends a right angle at the origin is
BITSAT - 2019
BITSAT
Mathematics
circle
The locus of centre of a circle which passes through the origin and cuts off a length of $4$ unit from the line $x = 3$ is
BITSAT - 2009
BITSAT
Mathematics
circle
If the lines $2x - 3y = 5$ and $3x - 4y = 7$ are two diameters of a circle of radius $7$, then the equation of the circle is
BITSAT - 2008
BITSAT
Mathematics
circle
The inverse of the point $(1, 2)$ with respect to the circle $x^2 + y^2 - 4x - 6y + 9 = 0$, is
BITSAT - 2008
BITSAT
Mathematics
circle
The radius of the circle with the polar equation $r^2 - 8r( \sqrt{3} \, \cos \, \theta + \sin \, \theta) + 15 = 0$ is
BITSAT - 2008
BITSAT
Mathematics
circle