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Question:
Which of the following on reaction with NaOI will give yellow precipitates?
(A) Phenylethanone
(B) Sec-Butyl alcohol
(C) Phenylethanal
(D) Methyl n-propylketone
Choose the correct answer from the options given below:
Which of the following on reaction with NaOI will give yellow precipitates?
(A) Phenylethanone
(B) Sec-Butyl alcohol
(C) Phenylethanal
(D) Methyl n-propylketone
Choose the correct answer from the options given below:
(A) Phenylethanone
(B) Sec-Butyl alcohol
(C) Phenylethanal
(D) Methyl n-propylketone
Choose the correct answer from the options given below:
Updated On: Nov 2, 2024
- A, B, and D only
- A, B, and C only
- A, B, C, and D
- B, C, and D only
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The Correct Option is B
Solution and Explanation
Sodium iodide in the presence of iodine (NaOI) reacts with certain carbonyl compounds to give yellow precipitates. Phenylethanone, sec-butyl alcohol (secondary alcohol), and phenylethanal (aldehyde) all react with NaOI to form yellow precipitates. Methyl n-propylketone is less likely to form a yellow precipitate under these conditions.
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