In a p-n junction diode under forward bias, the charge carriers responsible for current flow in the external circuit are free electrons. These electrons are present in the n-type material, and they move towards the p-type material. The free electrons from the n-side travel through the external circuit to the p-side, where they recombine with holes. This flow of free electrons constitutes the current in the connecting wire.
In a forward-biased p-n junction diode, the electrons from the n-side and the holes from the p-side move toward the junction. However, in the external connecting wire, the current is due to the movement of \(\textbf{free electrons}\), as electrons are the actual charge carriers in metal conductors (wires). Holes contribute to current only within the semiconductor, not in the external circuit.
Match the following types of nuclei with examples shown: 
Charges are uniformly spread on the surface of a conducting sphere. The electric field from the center of the sphere in a point outside the sphere varies with distance \( r \) from the center as 
Match the following:
In the following, \( [x] \) denotes the greatest integer less than or equal to \( x \). 
Choose the correct answer from the options given below:
For x < 0:
f(x) = ex + ax
For x ≥ 0:
f(x) = b(x - 1)2