Two point masses of 0.3 kg and 0.7 kg are fixed at the ends of a rod of length 1.4 m and of negligible mass. The rod is set rotating about an axis perpendicular to its length with a uniform angular speed. The point on the rod through which the axis should pass in order that the work required for rotation of the rod is minimum, is located at a distance of
Work done $W=\frac{1}{2}I\omega^2$ If x is the distance of mass 0.3 kg from the centre of mass, we will have, $I=(0.3)x^2+(0.7)(1.4-x)^2$ For work to be minimum, the moment of inertia (/) should be minimum, or or $2(0.3x)-2(0.7)(1.4-x)=0$ or $(0.3)x=(0.7)(1.4-x)$ $\Rightarrow x=\frac{(0.7)(1.4)}{0.3+0.7}=0.98m$
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Top Questions on System of Particles & Rotational Motion
The system of particles refers to the extended body which is considered a rigid body most of the time for simple or easy understanding. A rigid body is a body with a perfectly definite and unchangeable shape.
The distance between the pair of particles in such a body does not replace or alter. Rotational motion can be described as the motion of a rigid body originates in such a manner that all of its particles move in a circle about an axis with a common angular velocity.
The few common examples of rotational motion are the motion of the blade of a windmill and periodic motion.