Question:

To solve the equation x = 2 cos x using Newton-Raphson's method, which one of the following iterations should be used ?

Updated On: Jul 17, 2024
  • \(x_{n+1}=x_n-\frac{x_n-2\cos x_n}{1+2\sin x_n}\)
  • \(x_{n+1}=x_n+\frac{x_n-2\cos x_n}{1+2\sin x_n}\)
  • \(x_{n+1}=x_n+\frac{1+2\sin x_n}{x_n-2\cos x_n}\)
  • \(x_{n+1}=x_n-\frac{1+2\sin x_n}{x_n-2\cos x_n}\)
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The Correct Option is A

Solution and Explanation

The correct option is (A) : \(x_{n+1}=x_n-\frac{x_n-2\cos x_n}{1+2\sin x_n}\).
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