\(|x^{2}-8x+15|=2x-7\)
Case-I : \(x\geq 5\)
\(x^{2}-10x+22=0\)
\(x=\frac{10\pm \sqrt{12}}{2}=5\pm \sqrt{3}\)
then \(x= 5+\sqrt{3}\)
Case-II : \(\frac{7}{2}\leq x\leq 5\)
\(x^{2}-8x+15=7-2x\)
\(x^{2}-6x+8=0\)
\(x=4\)
Therefore, the sum of the roots \(= 5+\sqrt{3}+4=9+\sqrt{3}\)
So, The correct option is (C): 9 + \(\sqrt{3}\)
A polynomial that has two roots or is of degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b, and c are the real numbers.
Consider the following equation ax²+bx+c=0, where a≠0 and a, b, and c are real coefficients.
The solution of a quadratic equation can be found using the formula, x=((-b±√(b²-4ac))/2a)
Read More: Nature of Roots of Quadratic Equation