Question:

The study of radioactive decay results in the emission of particles, leading to four observations: (A) No change in atomic and mass number, (B) Atomic number decreases by 1, (C) Study of radioactive decay of unstable nuclei resulting in emission of a
particle leads us to four different observations listed below:
(A) Nochange in atomic number and mass number.
(B) Nochange in mass number but the atomic number decreases by 1.
(C) Nochange in mass number but the atomic number increases by 1.
(D) Atomic number decreases by 2 and the mass number decreases by 4.
Arrange the particles emitted in the above four cases in correct sequence:

Updated On: Nov 6, 2024
  • Alpha particle, positron, electron, photon
  • Alpha particle, electron, positron, photon
  • Photon, positron, electron, alpha particle
  • Alpha particle, positron, photon, electron
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The Correct Option is C

Solution and Explanation

- Case A: No change in atomic and mass numbers, which corresponds to photon emission.
- Case B: A decrease in atomic number by 1 corresponds to positron emission.
- Case C: An increase in atomic number by 1 corresponds to electron (beta) emission.
- Case D: A decrease in atomic number by 2 and mass number by 4 corresponds to alpha particle emission
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