The structures of major products A , B and C in the following reaction are sequence

Pay attention to the reagents and reaction conditions to identify the type of reaction occurring in each step. \(LiAlH_{4}\) is a strong reducing agent, commonly used to reduce nitriles to amines.




Step 1: Reaction with\(NaHSO_{3}\) and Dilute HCl (Formation of A)
The starting compound is butan-2-one. The reaction with \(NaHSO_{3}\)followed by dilute HCl results in the formation of a cyanohydrin. The CN\(^-\) ion from NaCN attacks the carbonyl carbon, and the oxygen picks up a proton. The major product \(A\) is 2-hydroxy-2-methylbutanenitrile.
Step 2: Reduction with\(LiAl_{4}\) (Formation of B)
Lithium aluminum hydride \(LiAlH_{4}\)is a strong reducing agent. It reduces the nitrile group (CN) to an amine group \((NH_{2})\). The product \(B\) is 1-amino-2-methylbutan-2-ol.
Step 3: Hydrolysis with \(HCl/H_{2}O\) and Heat (Formation of C)
The amine group in \(B\) is hydrolyzed with \(HCl/H_{2}O\)and heat (\( \Delta \)) into a carboxylic group.
The major product \(C\) is 2-hydroxy-2-methylbutanoic acid.
Conclusion
The structures of \(A\), \(B\), and \(C\) correspond to option (4).
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,
In organic chemistry, an alkyne is an unsaturated hydrocarbon containing at least one carbon-carbon triple bond. Alkynes are an organic molecule that contains triple bonds between the carbon atoms. Its general formula is CnH2n-2. They are also known as acetylenes. In this article, we will deal with the structure of alkynes.
Alkynes show three types of isomerism