To solve this question about the properties of ethyne, we need to analyze each statement given in the options:
Based on the analysis, the incorrect statement is: The carbon-carbon bonds in ethyne is weaker than that in ethene.
To determine the incorrect statement regarding ethyne, let's first understand its structure and properties.
Now let's evaluate each provided statement:
The C–C bonds in ethyne is shorter than that in ethene
This statement is correct. The triple bond in ethyne is shorter than the double bond in ethene because triple bonds have greater electron sharing, pulling the atoms closer together.
Both carbons are sp hybridised
This is also correct. As mentioned, ethyne carbons are \(sp\) hybridized.
Ethyne is linear
This statement is correct. Due to \(sp\) hybridization, ethyne has a linear molecular shape.
The carbon-carbon bonds in ethyne is weaker than that in ethene
This statement is incorrect. The carbon-carbon bond in ethyne (triple bond) is stronger than that in ethene (double bond) due to the triple bond having more shared electron pairs, making it stronger.
Conclusion: The incorrect statement is: "The carbon-carbon bonds in ethyne is weaker than that in ethene." The correct fact is that the carbon-carbon bond in ethyne is actually stronger.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,