Question:
The slope of the graph drawn by taking the frequency (in $10^{15}Hz$) of light incident on a photosensitive material on x-axis and the stopping potential (in volt) on y-axis is nearly
The slope of the graph drawn by taking the frequency (in $10^{15}Hz$) of light incident on a photosensitive material on x-axis and the stopping potential (in volt) on y-axis is nearly
Show Hint
For photoelectric effect graphs,
\[
\text{Slope}=\frac{h}{e}
\]
which is independent of the material used.
Updated On: Jun 17, 2026
- 8.250
- 2.420
- 4.125
- 3.175
Show Solution
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The Correct Option is C
Solution and Explanation
Concept:
Einstein's photoelectric equation is
\[
eV_s=hf-\phi
\]
or
\[
V_s=\frac{h}{e}f-\frac{\phi}{e}
\]
Hence the slope of the \(V_s-f\) graph is
\[
\frac{h}{e}
\]
Step 1: Calculate the slope.
\[ \frac{h}{e} = \frac{6.63\times10^{-34}} {1.6\times10^{-19}} \] \[ = 4.14\times10^{-15} \] Since frequency is plotted in units of \(10^{15}Hz\), \[ Slope = 4.14 \] \[ \approx4.125 \] \[ \boxed{4.125} \]
Step 1: Calculate the slope.
\[ \frac{h}{e} = \frac{6.63\times10^{-34}} {1.6\times10^{-19}} \] \[ = 4.14\times10^{-15} \] Since frequency is plotted in units of \(10^{15}Hz\), \[ Slope = 4.14 \] \[ \approx4.125 \] \[ \boxed{4.125} \]
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