Question:
The reaction of Toluenesulfonyl chloride with a primary amine forms a product that is:
The reaction of Toluenesulfonyl chloride with a primary amine forms a product that is:
Show Hint
Hinsberg Test:
Primary amine $\rightarrow$ Product soluble in alkali
Secondary amine $\rightarrow$ Product insoluble in alkali
Tertiary amine $\rightarrow$ No sulfonamide formation
Updated On: Jun 17, 2026
- Soluble in alkali
- Insoluble in alkali
- Soluble in water but insoluble in acids
- Liquid at room temperature
Show Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Concept:
The reaction of amines with p-toluenesulfonyl chloride is known as the Hinsberg test. This test is used to distinguish primary, secondary and tertiary amines.
Step 1: Reaction of primary amine with Hinsberg reagent. A primary amine reacts with p-toluenesulfonyl chloride. \[ \mathrm{RNH_2 + TsCl} \rightarrow \mathrm{TsNHR} \] where Ts represents the tosyl group.
Step 2: Nature of the product. The product still contains an acidic hydrogen attached to nitrogen. Hence it can react with alkali. \[ \mathrm{TsNHR + NaOH} \rightarrow \mathrm{Soluble\ sodium\ salt} \]
Step 3: Consequence. Because the sodium salt is formed, the product dissolves in alkali. Therefore the product is soluble in alkali. \[ \boxed{\text{Option (1)}} \]
Step 1: Reaction of primary amine with Hinsberg reagent. A primary amine reacts with p-toluenesulfonyl chloride. \[ \mathrm{RNH_2 + TsCl} \rightarrow \mathrm{TsNHR} \] where Ts represents the tosyl group.
Step 2: Nature of the product. The product still contains an acidic hydrogen attached to nitrogen. Hence it can react with alkali. \[ \mathrm{TsNHR + NaOH} \rightarrow \mathrm{Soluble\ sodium\ salt} \]
Step 3: Consequence. Because the sodium salt is formed, the product dissolves in alkali. Therefore the product is soluble in alkali. \[ \boxed{\text{Option (1)}} \]
Was this answer helpful?
0
0
Top TS EAMCET Chemistry Questions
- A, B and C are three biomolecules. The results of the tests performed on them are given below :A, B and C are respectively :
Molisch's lest Barfoed Test Biuret Test A Positive Negative Negativde B Positive Positive Negative C Negative Negative Positive - 1 mole of $H_2$ and 2 moles of $I_2$ are taken initially in a 2 litre vessel. The number of moles of $H_2$ at equilibrium is 0.2. Then the number of moles of $I_2$ and HI at equilibrium is
- The pH of a buffer containing equal molarconcentration of a weak base and its chloride ( $K_b$ for weak base = $2 \times 10^{-5}$, log 2 = 0.3) is
- Atomic radius (pm) of Al, Si, N and F respectively is
- Consider the following electrode process of a cell, $ {Cl^{-1} -> \frac{1}{2} Cl_2 + e^{-}}$ $ {[MCl + e^{-} -> M + Cl^{-} ] }$ If EMF of this cell is $-1.140\, V$ and $E^0$ value of the cell is $-0.55\,V$ at $298\,K$, the value of the equilibrium constant of the sparingly soluble salt MCl is in the order of
View More Questions
Top TS EAMCET Chemistry in Everyday Life Questions
- Identify the set of molecules which act as bleaching agents only by oxidation
- Which of the following is used in liquid detergents?
- Which radical is responsible for depletion of ozone in stratosphere?
- The vitamin that can be stored in the body and whose deficiency results in disease is:
- The drug which is obtained from opium poppy and its use are respectively:
View More Questions
Top TS EAMCET Questions
- A bag contains $5$ red balls, $3$ black balls and $4$ white balls are drawn at random. The probability that they are not of same colour is
- If $cosec\, \theta - \cot \theta = 2017$, then quadrant in which $\theta $ lies is
- If $a$ is a unit vector, then $| a \times \hat{ i }|^{2}+| a \times \hat{ j }|^{2}+| a \times \hat{ k }|^{2}=$
- $A$ straight line makes an intercept on the $Y$-axis twice as long as that on $X$-axis and is at a unit distance from the origin. Then the line is represented by the equations
- Let $S$ and $S'$ be the foci of an ellipse and B be one end of its minor axis. If $SBS'$ is an isosceles right angled triangle then the eccentricity of the ellipse is
View More Questions