The given reaction involves the oxidation of hydrogen gas to H$^+$ ions and the reduction of AgCl to Ag. This is consistent with the following electrode reactions:
Anode (oxidation): H$_2 \to$ 2H$^+ + 2e^-$
Cathode (reduction): AgCl + e$^- \to$ Ag + Cl$^-$ \end{itemize}
The correct galvanic cell setup corresponding to this reaction is: \[ \text{Pt} \vert \text{H}_2(\text{g}) \vert \text{HCl(sol$^n$)} \vert \text{AgCl(s)} \vert \text{Ag} \] Here, the HCl provides the H$^+$ ions required for the anode reaction, and AgCl serves as the source of Ag$^+$ for the cathode reaction.
Calculate the potential for half-cell containing 0.01 M K\(_2\)Cr\(_2\)O\(_7\)(aq), 0.01 M Cr\(^{3+}\)(aq), and 1.0 x 10\(^{-4}\) M H\(^+\)(aq).

Given below are two statements:
Statement I: Benzene is nitrated to give nitrobenzene, which on further treatment with \( \text{CH}_3\text{COCl} / \text{AlCl}_3 \) will give the product shown. 
Statement II: \( -\text{NO}_2 \) group is a meta-directing and deactivating group.
In the light of the above statements, choose the most appropriate answer from the options given below.