Select Goal &
City
Select Goal
Explore
Question:
The rate of a reaction quadruples when temperature changes from 27°c to 57°c. Calculate the energy of activation
Given R=8.314 J K-1 mol-1, log 4=0.6021
The rate of a reaction quadruples when temperature changes from 27°c to 57°c. Calculate the energy of activation
Given R=8.314 J K-1 mol-1, log 4=0.6021
Given R=8.314 J K-1 mol-1, log 4=0.6021
Updated On: Sep 18, 2024
- 38.04 KJ/mol
- 380.4 KJ/mol
- 3.80 KJ/mol
- 3804 KJ/mol
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
The correct option is (A): 38.04 KJ/mol
Was this answer helpful?
3
4
Top Questions on Chemical Reactions
- For given reaction:
‘P’ is- NEET (UG) - 2024
- Chemistry
- Chemical Reactions
- Identify the correct reagents that would bring about the following transformation.
- NEET (UG) - 2024
- Chemistry
- Chemical Reactions
- Identify the major product C formed in the following reaction sequence:
- NEET (UG) - 2024
- Chemistry
- Chemical Reactions
- The products A and B obtained int he following reactions, respectively, are
3ROH+PCI3→3RCI+A
ROH+PCI5→RCI+HCI+B- NEET (UG) - 2024
- Chemistry
- Chemical Reactions
- For the reaction 2A⇋ B + C, KC = 4 × 10–3 . At a given time, the composition of reaction mixture is: [A] = [B] = [C] = 2 × 10–3 M. Then, which of the following is correct?
- NEET (UG) - 2024
- Chemistry
- Chemical Reactions
View More Questions
Questions Asked in NEET exam
- A metallic bar of Young’s modulus, 0.5 × 1011 N m–2 and coefficient of linear thermal expansion 10–5 °C–1, length 1 m and area of cross-section 10–3 m2 is heated from 0°C to 100°C without expansion or bending. The compressive force developed in it is :
- NEET (UG) - 2024
- Youngs double slit experiment
- The E° value for the Mn3+/Mn2+ couple is more positive than that of Cr3+/Cr2+ or Fe3+/Fe2+ due to change of
- NEET (UG) - 2024
- Electronic configuration of atoms and ions
- A light ray enters through a right angled prism at point P with the angle of incidence 30° as shown in figure. It travels through the prism parallel to its base BC and emerges along the face AC. The refractive index of the prism is :
- NEET (UG) - 2024
- Refraction Through A Prism
- \(^{290}_{82}X\stackrel{\alpha}{\rightarrow}Y\stackrel{e^+}{\rightarrow}Z\stackrel{\beta^-}{\rightarrow}P\stackrel{e^-}{\rightarrow}Q\)
In the nuclear emission stated above, the mass number and atomic number of the product Q respectively, are :- NEET (UG) - 2024
- Nuclear physics
- A compound X contains 32% of A, 20% of B and remaining percentage of C. Then, the empirical formula of X is:
(Given atomic masses of A=64; B=40; C=32 u)- NEET (UG) - 2024
- Some basic concepts of chemistry
View More Questions
NEET Notification
Jharkhand NEET UG 2024 Round 2 Choice Filling Extended, Apply Now!Sep 18, 2024Jharkhand NEET UG Counselling 2024 Round 2 Choice Filling last date has been extended till September 24, 2024. The round 2 seat allotment result will be released on September 27, 2024. Students can download the result from the official website jceceb.jharkhand.gov.in.
SUBSCRIBE TO OUR NEWS LETTER
COLLEGE NOTIFICATIONSEXAM NOTIFICATIONSNEWS UPDATES
Download the Collegedunia app on 
© 2024 Collegedunia Web Pvt. Ltd. All Rights Reserved