Question:

The magnetic moment of a transition metal compound has been calculated to be 3.87 B.M. The metal ion is

Updated On: Sep 09, 2024
  • $T_1^{2+}$
  • $Mn ^{2+}$
  • $V ^{2+}$
  • $Cr ^{2+}$
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The Correct Option is C

Solution and Explanation

A substance that may repel or attract other substances is referred to as a "magnetic material." The arrangement of electrons, also known as the magnetic moment of the material, determines whether these materials are attracted to or repel one another. The magnetic dipole moment of an object is a measure of the torque experienced by it in the presence of a magnetic field. 

Cr+2:[Ar],3d4,4s0 n=4, μ=4(4+2)​=24​ 
=4.89BM 

Mn+2:[Ar],3d5,4s0 n=5,μ=5(5+2)​=35​ 
=5.91BM 

V+2:[Ar],3d3,4s0 n=3,μ=3(3+2)​=15​ 
=3.87BM 

Ti+2:[Ar],3d2,4s0 n=2,μ=2(2+2)​=8​ 
=2.82BM

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JEE Main Notification

Concepts Used:

D and F Block Elements

The d-block elements are placed in groups 3-12 and F-block elements with 4f and 5f orbital filled progressively. The general electronic configuration of d block elements and f- block elements are (n-1) d 1-10 ns 1-2 and (n-2) f 1-14 (n-1) d1 ns2 respectively. They are commonly known as transition elements because they exhibit multiple oxidation states because of the d-d transition which is possible by the availability of vacant d orbitals in these elements. 

They have variable Oxidation States as well as are good catalysts because they provide a large surface area for the absorption of reaction. They show variable oxidation states to form intermediate with reactants easily. They are mostly lanthanoids and show lanthanoid contraction. Since differentiating electrons enter in an anti-penultimate f subshell. Therefore, these elements are also called inner transition elements.

Read More: The d and f block elements