Question:

The hybridization of boron in diborane (B2H6) is:

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Each boron bonds to 4 H directions (2 terminal + 2 bridging), tetrahedral sp3.
Updated On: Jul 3, 2026
  • \(sp\)
  • \(sp^2\)
  • \(sp^3\)
  • \(sp^3d\)
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The Correct Option is C

Solution and Explanation

Step 1: Diborane has 4 terminal H and 2 bridging H.
Step 2: Each boron bonds to 2 terminal H (normal bonds) and 2 bridging H (3c-2e bonds), 4 directions total.
Step 3: 4 tetrahedral directions require sp3 hybridization.
\[\boxed{sp^3}\]
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