Step 1: Ozonolysis cleaves a carbon-carbon double bond and replaces it with two carbonyl groups, converting the alkene into two separate carbonyl compounds at the position of the original double bond.
Step 2: For the product to be propanal, $CH_3CH_2CHO$, exclusively as a single product rather than a mixture, both fragments produced by cleavage must be identical, which means the double bond must lie exactly at the center of a symmetric alkene.
Step 3: Consider hex-3-ene: $CH_3-CH_2-CH=CH-CH_2-CH_3$. The double bond is between C3 and C4, which is the exact center of the six-carbon chain.
Step 4: Ozonolysis cleaves between C3 and C4, giving two identical three-carbon fragments, each of which is propanal.
\[ CH_3CH_2CH=CHCH_2CH_3 \xrightarrow[Zn/H_2O]{1.\ O_3} 2\ CH_3CH_2CHO \]
Step 5: In contrast, hex-2-ene (cis or trans) has its double bond between C2 and C3, off-center, so ozonolysis gives a mixture of acetaldehyde and butanal, not propanal exclusively. Similarly, pent-2-ene gives a mixture of acetaldehyde and propanal, not propanal alone.
\[\boxed{\text{Hex-3-ene}}\]