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Question:
The complex $[CoF_{6}]^{4-}$ is
The complex $[CoF_{6}]^{4-}$ is
Updated On: Jun 3, 2024
- outer orbital and diamagnetic
- inner orbital and paramagnetic
- inner orbital and diamagnetic
- outer orbital and paramagnetic
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The Correct Option is D
Solution and Explanation
In $\left[ CoF _{6}\right]^{4-}$, central metal
Co is present as $Co ^{2+}$.
$C o^{2+}=[A r] 3 d^{7} 4 s^{0}$
Because of the presence of three unpaired electrons, the complex is paramagnetic. Moreover, $F^-$
ions occupy outer $d$-orbitals (ie, $nd$-orbitals), thus it is an outer orbital complex.
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Concepts Used:
Coordination Compounds
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
Coordination entity:
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
Ligands:
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.
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