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What is (are) number $(s)$ of unpaired electrons in the square planar $[Pt(CN)_4]^{2-}$ ion?
What is (are) number $(s)$ of unpaired electrons in the square planar $[Pt(CN)_4]^{2-}$ ion?
Updated On: Jun 14, 2022
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The Correct Option is D
Solution and Explanation
Outer electronic configuration of $Pt$ is $5 d^{9} 6 s^{1}$
Outer electronic configuration of $P t^{2+}$ is $5 d^{8}$.
As $C N^{-}$is strong field ligand, so pairing will take place.
Outer electronic configuration of $P t^{2+}$ is $5 d^{8}$.
As $C N^{-}$is strong field ligand, so pairing will take place.
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Concepts Used:
Coordination Compounds
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
Coordination entity:
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
Ligands:
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.
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