Question:
The coefficient of friction between object and substance, if we need to move an object of weight \(150\ \text{N}\) on a horizontal surface with a force of \(75\ \text{N}\), is
The coefficient of friction between object and substance, if we need to move an object of weight \(150\ \text{N}\) on a horizontal surface with a force of \(75\ \text{N}\), is
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For a body on a horizontal surface:
\[
\text{Limiting friction}= \mu N
\]
and
\[
N=W
\]
Always use the normal reaction while calculating frictional force.
Updated On: Jun 25, 2026
- \(0.8\)
- \(0.5\)
- \(0.7\)
- \(0.9\)
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The Correct Option is B
Solution and Explanation
Step 1: Write the formula for limiting friction.
The limiting friction acting on a body is given by \[ F=\mu N \] where \[ F=\text{frictional force}, \] \[ \mu=\text{coefficient of friction}, \] and \[ N=\text{normal reaction} \]
Step 2: Determine the normal reaction.
Since the object is placed on a horizontal surface, \[ N=W \] Given weight: \[ W=150\ \text{N} \] Hence, \[ N=150\ \text{N} \]
Step 3: Substitute the given values.
The force required to just move the object is \[ F=75\ \text{N} \] Using \[ F=\mu N, \] we get \[ 75=\mu(150) \] \[ \mu=\frac{75}{150} \] \[ \mu=\frac{1}{2} \] \[ \mu=0.5 \]
Step 4: Final conclusion.
Hence, the coefficient of friction is \[ \boxed{0.5} \]
The limiting friction acting on a body is given by \[ F=\mu N \] where \[ F=\text{frictional force}, \] \[ \mu=\text{coefficient of friction}, \] and \[ N=\text{normal reaction} \]
Step 2: Determine the normal reaction.
Since the object is placed on a horizontal surface, \[ N=W \] Given weight: \[ W=150\ \text{N} \] Hence, \[ N=150\ \text{N} \]
Step 3: Substitute the given values.
The force required to just move the object is \[ F=75\ \text{N} \] Using \[ F=\mu N, \] we get \[ 75=\mu(150) \] \[ \mu=\frac{75}{150} \] \[ \mu=\frac{1}{2} \] \[ \mu=0.5 \]
Step 4: Final conclusion.
Hence, the coefficient of friction is \[ \boxed{0.5} \]
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