Question:

The charge required for the reduction of 1 mol of MnO$_4^-$ to MnO$_2$ is

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When dealing with electrochemical reactions, remember that the number of Faradays required equals the number of moles of electrons involved in the reaction.
Updated On: Jun 18, 2025
  • 1 F
  • 3 F
  • 5 F
  • 6 F
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The Correct Option is C

Solution and Explanation

The reduction of MnO$_4^-$ to MnO$_2$ involves a change in the oxidation state of Mn from +7 to +2.
According to the balanced redox reaction, the number of electrons required to reduce 1 mole of MnO$_4^-$ is 5.
Thus, the total charge required for the reduction is 5 Faradays (F).
Hence, the correct option is (3) 5 F.
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