Question:
The Binding energy per nucleon of \(^7_3Li\) and \(^4_2He\) nuclei are 5.60 MeV and 7.06 MeV, respectively. In the nuclear reaction \(^7_3Li + ^1_1H \rightarrow ^4_2He + ^4_2He+Q\), the value of energy Q released is:
The Binding energy per nucleon of \(^7_3Li\) and \(^4_2He\) nuclei are 5.60 MeV and 7.06 MeV, respectively. In the nuclear reaction \(^7_3Li + ^1_1H \rightarrow ^4_2He + ^4_2He+Q\), the value of energy Q released is:
Updated On: May 22, 2024
- -2.4MeV
- 8.4MeV
- 17.3MeV
- 19.6MeV
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The Correct Option is C
Solution and Explanation
The correct option (C): 17.3MeV
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