To determine the exceptions to the octet rule, analyze each molecule:
CO$_2$: Follows the octet rule. (C has 8 electrons in its valence shell.
NO$_2$: Exception. It has an odd number of valence electrons (11), making it a free radical.
H$_2$SO$_4$: Follows the octet rule.
BF$_3$: Exception. Boron has only 6 electrons in its valence shell (electron-deficient compound).
CH$_4$: Follows the octet rule.
SiF$_4$: Follows the octet rule.
ClO$_2$: Exception. It is a free radical with an odd number of valence electrons.
PCl$_5$: Exception. Phosphorus has 10 valence electrons (expanded octet).
BeF$_2$:Exception. Beryllium has only 4 valence electrons (electron-deficient compound).
C$_2$H$_6$: Follows the octet rule.
CHCl$_3$: Follows the octet rule.
CBr$_4$: Follows the octet rule.
Molecules that are exceptions to the octet rule:
\[\text{NO}_2, \text{BF}_3, \text{ClO}_2, \text{PCl}_5, \text{BeF}_2\]
Total number of exceptions = 6.
Final Answer:\[6\]
List-I (Compound / Species) | List-II (Shape / Geometry) |
---|---|
(A) \(SF_4\) | (I) Tetrahedral |
(B) \(BrF_3\) | (II) Pyramidal |
(C) \(BrO_{3}^{-}\) | (III) See saw |
(D) \(NH^{+}_{4}\) | (IV) Bent T-shape |
List - I | List - II |
---|---|
(A) ICl | (IV) Linear |
(B) ICl3 | (I) T-Shape |
(C) ClF5 | (II) Square pyramidal |
(D) IF7 | (III) Pentagonal bipyramidal |
A body of mass 1000 kg is moving horizontally with a velocity of 6 m/s. If 200 kg extra mass is added, the final velocity (in m/s) is: