Number of geometrical isomers possible for the given structure is/are ___________.
Correct Answer: 4
Approach Solution - 1
To determine the number of geometrical isomers for the given structure:
Identifying Stereocenters: The given structure contains three stereocenters, which influence the overall geometric configurations.
Counting Geometrical Isomers: The maximum potential geometric isomers can be calculated using the formula:
Total Geometrical Isomers = 2n
where n is the number of stereocenters. In this case:
23 = 8
However, due to symmetry in the molecule, some configurations are equivalent, reducing the number of unique geometrical isomers.
Final Count: Considering the symmetry and equivalent configurations, the total number of unique geometrical isomers for the given structure is 4.
Approach Solution -2
To determine the number of geometrical isomers possible for the given structure, follow these steps:
- The compound depicted has two double bonds. Each of these double bonds can exist in either a cis or trans configuration, depending on the spatial arrangement of attached groups.
- The first double bond is between the two carbon atoms connected to hydrogen (H) and deuterium (D). This bond can have two isomers: either the H atoms on opposite sides (trans) or on the same side (cis).
- The second double bond is also between two carbon atoms, attached to different hydrogen (H) and deuterium (D) atoms, allowing for a similar cis or trans configuration.
- Since each of the two double bonds can independently exist as cis or trans, the total number of geometrical isomers is given by multiplying the isomer possibilities for each double bond: \(2 \times 2 = 4\).
- Therefore, the total number of geometrical isomers is 4.
Conclusively, the solution meets the provided range of 4,4. Thus, the number of geometrical isomers possible is 4.
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