
The dipole moment is a vector quantity. In the trans isomer of 2-butene, the dipoles of substituents are equal in magnitude but opposite in direction, resulting in a net dipole moment of zero (\(\mu = 0\)). However, in the cis isomer, the dipoles do not cancel out, making the molecule polar with \(\mu > 0\). Thus, the dipole moment of the cis form is greater than the trans form.
Cis isomer: \(\mu > 0\), Trans isomer: \(\mu = 0\).
Therefore, both the assertion and reason are true, and the reason correctly explains the assertion.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)



