Select Goal &
City
Select Goal
Explore
Question:
Match the electronic configurations in List-I with appropriate metal complex ions in List-II and choose the correct option.
[Atomic Number: Fe = 26, Mn = 25, Co = 27]
List-I List-II (P) \(t^6_{2g} e^0_g\) (1) \( [Fe(H_2O)_6]^{2+}\) (Q) \(t^3_{2g} e^2_g\) (2) \( [Mn(H_2O)_6]^{2+}\) (R) \(e^2t^3_{2}\) (3) \( [Co(NH_3)_6]^{3+}\) (S) \(t^4_{2g} e^2_g\) (4) \([FeCl_4]^-\) (5) \( [CoCl_4]^{2-}\)
Match the electronic configurations in List-I with appropriate metal complex ions in List-II and choose the correct option.
[Atomic Number: Fe = 26, Mn = 25, Co = 27]
[Atomic Number: Fe = 26, Mn = 25, Co = 27]
| List-I | List-II | ||
| (P) | \(t^6_{2g} e^0_g\) | (1) | \( [Fe(H_2O)_6]^{2+}\) |
| (Q) | \(t^3_{2g} e^2_g\) | (2) | \( [Mn(H_2O)_6]^{2+}\) |
| (R) | \(e^2t^3_{2}\) | (3) | \( [Co(NH_3)_6]^{3+}\) |
| (S) | \(t^4_{2g} e^2_g\) | (4) | \([FeCl_4]^-\) |
| (5) | \( [CoCl_4]^{2-}\) |
Updated On: May 24, 2024
P →1; Q→ 4; R →2; S →3
P →1; Q→ 2; R →4; S →5
P →3; Q→ 2; R →5; S →1
P →3; Q→ 2; R →4; S →1
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Correct option is (D) P → 3; Q → 2; R → 4; S → 1
Was this answer helpful?
2
0
Top Questions on Stoichiometry and Stoichiometric Calculations
- The strength of $50$ volume solution of hydrogen peroxide is _____$g / L$ (Nearest integer)
Given: Molar mass of $H _2 O _2$ is $34\, g \, mol ^{-1}$ Molar volume of gas at $STP =22.7\, L$- JEE Main - 2023
- Chemistry
- Stoichiometry and Stoichiometric Calculations
- What is the correct order of acidity of the protons marked A-D in the given compounds?
- JEE Main - 2023
- Chemistry
- Stoichiometry and Stoichiometric Calculations
- When a hydrocarbon A undergoes combustion in the presence of air, it requirs 9.5 equivalents of oxygen and produces 3 equivalents of water. What is the molecular formula of A?
- JEE Main - 2023
- Chemistry
- Stoichiometry and Stoichiometric Calculations
- Match the reactions in List-I with the features of their products in List-II and choose the correct option
List-I List-II (P) (-)-1-Bromo-2-ethylpentane 
(single enantiomer)(1) Inversion of configuration (Q) (-)-2-Bromopentane 
(single enantiomer)(2) Retention of configuration (R) (-)-3- Bromo-3-methylhexane 
(single enantiometer)(3) Mixture of enantiomers (S) 
(single enantiometer)(4) Mixture of structural isomers (5) Mixture of diastereomers - JEE Advanced - 2023
- Chemistry
- Stoichiometry and Stoichiometric Calculations
- Find the correct stoichiometric coefficients in the following redox equation:
xH+ + yC6H5CH3 + wMnO-4 → aH2O + bMn2+ + tC6H5COOH- CUET (UG) - 2023
- Chemistry
- Stoichiometry and Stoichiometric Calculations
View More Questions
Questions Asked in JEE Advanced exam
- A region in the form of an equilateral triangle (in x-y plane) of height L has a uniform magnetic field 𝐵⃗ pointing in the +z-direction. A conducting loop PQR, in the form of an equilateral triangle of the same height 𝐿, is placed in the x-y plane with its vertex P at x = 0 in the orientation shown in the figure. At 𝑡 = 0, the loop starts entering the region of the magnetic field with a uniform velocity 𝑣 along the +x-direction. The plane of the loop and its orientation remain unchanged throughout its motion.
Which of the following graph best depicts the variation of the induced emf (E) in the loop as a function of the distance (𝑥) starting from 𝑥 = 0? - Two beads, each with charge q and mass m, are on a horizontal, frictionless, non-conducting, circular hoop of radius R. One of the beads is glued to the hoop at some point, while the other one performs small oscillations about its equilibrium position along the hoop. The square of the angular frequency of the small oscillations is given by [ \(\epsilon_0 \)is the permittivity of free space.]
- JEE Advanced - 2024
- Moving charges and magnetism
- A group of 9 students, s1, s2,…., s9, is to be divided to form three teams X, Y and Z of sizes 2, 3, and 4, respectively. Suppose that s1 cannot be selected for the team X and s2 cannot be selected for the team Y. Then the number of ways to form such teams, is _______.
- JEE Advanced - 2024
- Combinations
- Let \(\vec{p}=2\hat{i}+\hat{j}+3\hat{k}\) and \(\vec{q}=\hat{i}-\hat{j}+\hat{k}\). If for some real numbers α, β and γ we have
\(15\hat{i}+10\hat{j}+6\hat{k}=α(2\vec{p}+\vec{q})+β(\vec{p}-2\vec{q})+γ(\vec{p}\times\vec{q})\),
then the value of γ is ________.- JEE Advanced - 2024
- Vector Algebra
- Let X be a random variable, and let P(X = x) denote the probability that X takes the value x. Suppose that the points (x, P(X = x)), x = 0,1,2,3,4, lie on a fixed straight line in the xy -plane, and P(X = x) = 0 for all x ∈ R - {0,1,2,3,4}. If the mean of X is \(\frac{5}{2}\) , and the variance of X is α, then the value of 24α is ______.
- JEE Advanced - 2024
- Probability
View More Questions
Concepts Used:
Stoichiometry
Stoichiometry is founded on the law of conservation of mass where the total mass of the reactants equals the total mass of the products, leading to the insight that the relations among quantities of reactants and products typically form a ratio of positive integers. This means that if the amounts of the separate reactants are known, then the amount of the product can be calculated. Conversely, if one reactant has a known quantity and the quantity of the products can be empirically determined, then the amount of the other reactants can also be calculated.
Stoichiometry helps us determine how much substance is needed or is present. Things that can be measured are;
- Reactants and Products mass
- Molecular weight
- Chemical equations
- Formulas
Stoichiometric Coefficient
The Stoichiometric coefficient of any given component is the number of molecules and/or formula units that participate in the reaction as written.
Mole Ratios
The mass of one mole of a substance in grams is called molar mass. The molar mass of one mole of a substance is numerically equal to the atomic/molecular formula mass.
SUBSCRIBE TO OUR NEWS LETTER
COLLEGE NOTIFICATIONSEXAM NOTIFICATIONSNEWS UPDATES
Download the Collegedunia app on 
© 2024 Collegedunia Web Pvt. Ltd. All Rights Reserved