Question:

Let y ∈ R be such that the lines \(L_1:\frac{x+11}{1}=\frac{y+21}{2}=\frac{z+29}{3}\) and \(L_2:\frac{x+16}{3}=\frac{y+11}{2}=\frac{z+4}{\gamma}\) intersect. Let R1 be the point of intersection of L1 and L2. Let O = (0, 0 ,0), and \(\hat{n}\) denote a unit normal vector to the plane containing both the lines L1 and L2.
Match each entry in List-I to the correct entry in List-II.
List - IList - II
(P)γ equals(1)\(-\hat{i}-\hat{j}+\hat{k}\)
(Q)A possible choice for \(\hat{n}\) is(2)\(\sqrt{\frac{3}{2}}\)
(R)\(\overrightarrow{OR_1}\) equals(3)1
(S)A possible value of \(\overrightarrow{OR_1}.\hat{n}\) is(4)\(\frac{1}{\sqrt6}\hat{i}-\frac{2}{\sqrt6}\hat{j}+\frac{1}{\sqrt6}\hat{k}\)
  (5)\(\sqrt{\frac{2}{3}}\)
The correct option is

Updated On: Jun 10, 2024
  • (P) → (3) (Q) → (4) (R) → (1) (S) → (2)
  • (P) → (5) (Q) → (4) (R) → (1) (S) → (2)
  • (P) → (3) (Q) → (4) (R) → (1) (S) → (5)
  • (P) → (3) (Q) → (1) (R) → (4) (S) → (5)
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The Correct Option is C

Solution and Explanation

The correct option is (C):(P) → (3) (Q) → (4) (R) → (1) (S) → (5).
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