In the wet tests for identification of various cations by precipitation, which transition element cation doesn’t belong to group IV in qualitative inorganic analysis?
\(Fe^{3+}\)
\(Zn^{2+}\)
\(Co^{2+}\)
\(Ni^{2+}\)
Step 1: Understanding the Grouping of Cations in Qualitative Analysis
In qualitative inorganic analysis, cations are classified into groups based on their precipitation behavior with specific reagents. The classification is as follows:
Group III: Includes \(\text{Fe}^{3+}\), \(\text{Al}^{3+}\), and \(\text{Cr}^{3+}\), which precipitate as hydroxides in the presence of \(\text{NH}_4\text{OH}\) and \(\text{NH}_4\text{Cl}\).
Group IV: Includes \(\text{Zn}^{2+}\), \(\text{Co}^{2+}\), and \(\text{Ni}^{2+}\), which precipitate as sulfides in the presence of \(\text{H}_2\text{S}\) in neutral or slightly acidic medium.
Step 2: Analysis of the Cations
\(\text{Fe}^{3+}\): Belongs to Group III, as it forms \(\text{Fe(OH)}_3\) precipitate with \(\text{NH}_4\text{OH}\).
\(\text{Zn}^{2+}\), \(\text{Co}^{2+}\), \(\text{Ni}^{2+}\): Belong to Group IV, as they precipitate as sulfides (\(\text{ZnS}\), \(\text{CoS}\), \(\text{NiS}\)) with \(\text{H}_2\text{S}\).
Conclusion: \(\text{Fe}^{3+}\) does not belong to Group IV. Therefore, the correct answer is (1) \(\text{Fe}^{3+}\).
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,