Question:

Statement I: Among the following set of ionic species, [Cr³⁺, Mn²⁺]; [Ti⁴⁺, V²⁺]; [Sc³⁺, V⁴⁺] and [Co³⁺, Cu²⁺] three sets have both ions are coloured.
Statement II: Among the following set of ionic species [Lu³⁺, La³⁺]; [Ln³⁺, Ce⁴⁺]; [Yb²⁺, Eu²⁺] and [Nd³⁺, Sm³⁺] three sets have both ions diamagnetic in nature.

Updated On: Apr 13, 2026
  • Both Statement I and Statement II are correct.
  • Statement I is correct but Statement II is incorrect.
  • Statement I incorrect but Statement II is correct.
  • Both Statement I and Statement II are incorrect.
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The Correct Option is C

Solution and Explanation


Step 1: Explanation of Statement I.

The first statement involves ionic species that are coloured. Colour in ionic species is due to the presence of unpaired electrons in the d-orbitals, which can absorb visible light and appear coloured.
- [Cr³⁺, Mn²⁺]: Both are coloured because they have unpaired electrons in their d-orbitals.
- [Ti⁴⁺, V²⁺]: Ti⁴⁺ is colourless, as it has no d-electrons. V²⁺ is coloured due to unpaired electrons.
- [Sc³⁺, V⁴⁺]: Both are colourless due to the absence of d-electrons.
- [Co³⁺, Cu²⁺]: Both are coloured due to unpaired electrons.
Thus, Statement I is incorrect because not all of the given ionic species are coloured.
Step 2: Explanation of Statement II.

Statement II involves ionic species that are diamagnetic. Diamagnetism occurs when all electrons are paired, leading to no net magnetic moment.
- [Lu³⁺, La³⁺]: Both are diamagnetic because they have no unpaired electrons.
- [Ln³⁺, Ce⁴⁺]: Both are diamagnetic.
- [Yb²⁺, Eu²⁺]: Both are diamagnetic.
- [Nd³⁺, Sm³⁺]: Both are diamagnetic.
Thus, Statement II is correct as all of these species are diamagnetic. Final Answer: Statement I incorrect but Statement II is correct.
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