\(6\)
\(3\)
\(5\)3
\(2\)
\(4\)
Given that
\((5r + 4)\text{th term} = 25C_{5r+3}x^{5r+4}\)
\( (r − 1)^{1/4}\text{ term } = 25C_{r−2}x^ {r−1}\)
\(25C_{5r+3} x^{5r+4} = 25C_{r−2}\)
\((5r + 3) + (r − 2) = 25\)
\(6r+1=25\)
\(r=4\) (_Ans)